3x^2-36x=324

Solution for 3x^2-36x=324 equation:

3x^2-36x=324

We move all terms to the left:

3x^2-36x-(324)=0

a = 3; b = -36; c = -324;
Δ = b2-4ac
Δ = -362-4·3·(-324)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-72}{2*3}=\frac{-36}{6}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+72}{2*3}=\frac{108}{6}
=18
$